Askiitians Expert Soumyajit IIT-Kharagpur
Last Activity: 14 Years ago
Dear STUDENT NAME,
Ans:- The given function is f(x)=x+1/x the 1st order derivative is=1-1/x²
The 2nd order derivative is=2/x³ Putting dy/dx=0 we get, x=+1, -1 Again checking the conditions for max && min in the 2nd order derivative we get the values as
Max value= -2
Min value=+2
Look carefully that the max value is less than that of the min value.
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Soumyajit Das IIT Kharagpur