Find the derivative of y = arcsinh(1-x/1+x)derivatives

Find the derivative of y = arcsinh(1-x/1+x)derivatives


1 Answers

Askiitians Expert Bharath-IITD
23 Points
12 years ago

Dear Satyam,

                    we know that d/dx(arcsinh x) = 1/√(x2+1)

So here in place of x we have (1-x/1+x)

And d/dx(1-x/1+x)= [ (1+x) d/dx(1-x) - (1-x) d/dx(1+x) ] / (1+x)2

                           = [ (1+x) *(-1) - (1-x) *1 ] / (1+x)2

                           = -2/ (1+x)2

now dy/dx = 1/ √((1-x/1+x)2+1) *  d/dx(1-x/1+x)

                =[ (1+x)/√2(x2+1) ] *  -2/ (1+x)2

                      = -√2/ √(x2+1)*(1+x)


Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
are all IITians and here to help you in your IIT JEE preparation.

All the best  !!!



Askiitians Experts

Adapa Bharath

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy


Get your questions answered by the expert for free