The parabolas y2=4ax and x2=4by intersect orthogonally at point P(x1,y1) where x1,y1=0 is not possible, then
(A)b=a2
(B)b=a3
(C)b3=a2
(D)None of these.
Jayati Sindhu
16 Years agoGrade 12
1 Answer
Jitender Singh
12 Years ago
Ans:
If two parabolas intersect orthogonally, then the tangents at points of intersection must be perpendicular. Lets find points of intersection:
...(1)
...(2)
Put y from (2) in (1)
Let the slope of tangent to parabola (1) & (2) be m1& m2respectively.