Chandrakesh Shukla , 16 Years ago
Grade 12
Differential Calculus> Limits...
1 Answers
dhulipalla aravind aravind
√XSQARE+10-√19⁄X-3
RATIONALISING IT WEGET
XSQARE+10-19⁄(X-3)•(√XSQARE+10-√19)
=XSQARE-9/(√SQARE+10-√19)•(X-30)
=X+3/√XSQARE+10+√19
APPLYING LIMIT
3+3/√10+9+√19
=3/√19
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