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x 2 y 2 dx+1/xdy=0

x2y2dx+1/xdy=0

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
148 Points
12 years ago

Dear Jithi

x2y2dx+1/xdy=0

 x2y2dx+=-1/x dy

x3 dx = -dy/y2

x3 dx =-1/y2 dy

x4/4  = 1/y  +c

 

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