Let ABCD be a rectangle with AB=a and BC=b.Suppose r1 is the radius of the circle passing through A and B and touching CD ; r2 is the radius of the circle passing through B and C and touching AD then prove that
r1=a2+4b2/8b and r2=b3+4a2b/8ab
Let ABCD be a rectangle with AB=a and BC=b.Suppose r1 is the radius of the circle passing through A and B and touching CD ; r2 is the radius of the circle passing through B and C and touching AD then prove that
r1=a2+4b2/8b and r2=b3+4a2b/8ab









