2^|x+1|-2^x=|2^x-1|+1

Dear akash

2^|x+1|-2^x=|2^x-1|+1

case 1   x <-1

2^-(x+1)-2^x=1-2^x+1

so -(x+1) =1

 x=-2   it is a solution

case 2  -1≤x<0

so  

2^(x+1)-2^x=-2^x+1+1

 2^(x+1) =2

 x+1=1

 x=0     not a solution

case x≥0

so

2^(x+1)-2^x=2^x-1+1

  2^(x+1) =2^{(x+1)   this is true for any vvalue of x}

^{so final solution is x=-2 and all value of} x≥0

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