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|x^2+4x+3|+2x+5=0 solve
Dear akash
|x^2+4x+3|+2x+5=0
|x^2+4x+3| =-(2x+5)
so for solution exists
2x+5 ≤0
x≤-2.5
now check for x^2+4x+3≤0
(x+3)(x+1)≤0
-3 ≤ x≤-1
case 1 x≤-3
x^2+4x+3 =-(2x+5)
or x^2+6x+8| =0
x=-4 and -2
-2 is not a solution
case 2 -3 <x≤-2.5
-(x^2+4x+3) =-(2x+5)
x^2+2x-2 =0
x= -1 ±√3
so x= -1 -√3 is accepted solution
so final solution is x =-4 and -1-√3
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