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(|x+2|-x)/x<2 solve eq
dear akash
(|x+2|-x)/x<2
case 1 x<-2
so (-(x+2)-x)/x < 2
(-2x -2)/x <2
or (x+1)/x > 1
1+ 1/x >1
or 1/x >0
since x<-2 so no solution is possible
case -2 ≤x <0
so now
((x+2)-x)/x<2 2/x <2 1/x<1
((x+2)-x)/x<2
2/x <2
1/x<1
since lest side is negative so it is valid for all value -2 ≤x <0
case 3 x≥0
so
x>1
so solution is possible for x>1
so final solution -2 ≤x <0 and x>1
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