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∫1⁄1+x 2 +y 2 dx

∫1⁄1+x2+y2dx

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear Jithu

I = ∫1⁄(1+x2+y2)  dx

I = ∫1⁄√(1+y2)2+x2)  dx 

 

   = 1/ √(1+y2)   tan -1 { x/√(1+y2)}  +  C

 

here y is taken as constant because nothing is given about y

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