∫1⁄1+x 2 +y 2 dx



1 Answers

Badiuddin askIITians.ismu Expert
148 Points
12 years ago

Dear Jithu

I = ∫1⁄(1+x2+y2)  dx

I = ∫1⁄√(1+y2)2+x2)  dx 


   = 1/ √(1+y2)   tan -1 { x/√(1+y2)}  +  C


here y is taken as constant because nothing is given about y

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