The graph of the fns y=f(x) is symmetrical about the line x=2 then

a f(x+2)=f(x-2)

b f(2+x)=f(2-x)

c f(x)=f(-x)

d f(x)=-[f(-x)]

Question

The graph of the fns y=f(x) is symmetrical about the line x=2 then a f(x+2)=f(x-2) b f(2+x)=f(2-x) c f(x)=f(-x) d f(x)=-[f(-x)]

Sunil Kumar · Answer

Answer : (b) f(2+x)=f(2-x) check for thr conditions of symmetry. Thanks & Regards Sunil Kumar, askIITians Faculty M.Sc., IIT Kharagpur

Himanshu Mohan · Answer

can u give me solution plz

ayush kumar · Answer

since function is symmetric about x=2; value of function will be identical on both side of 2 or we can say x=2 is a mirror . so whatever distance you move from x=2 in right means you are moving same distance in left. i.e. if you are moving x in the right you are also moving x in the left and therefore these two will have same value. i.e. f(2+x)=f(2-x)

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The graph of the fns y=f(x) is symmetrical about the line x=2 then a f(x+2)=f(x-2) b f(2+x)=f(2-x) c f(x)=f(-x) d f(x)=-[f(-x)]

The graph of the fns y=f(x) is symmetrical about the line x=2 then

a f(x+2)=f(x-2)

b f(2+x)=f(2-x)

c f(x)=f(-x)

d f(x)=-[f(-x)]

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