The graph of the fns y=f(x) is symmetrical about the line x=2 then
a f(x+2)=f(x-2)
b f(2+x)=f(2-x)
c f(x)=f(-x)
d f(x)=-[f(-x)]
The graph of the fns y=f(x) is symmetrical about the line x=2 then
a f(x+2)=f(x-2)
b f(2+x)=f(2-x)
c f(x)=f(-x)
d f(x)=-[f(-x)]











