(x-sinx)/x^3 ltx-0

THE ANSWER S 0

WHAT IS ^?????

IF,IT INDICATES POWER,,

SO,

IT IS 0/0 FORM,,,

NOW,,APPLYING L''HOSPITAL RULE

1-COSX/3X^2;

AGAIN APPLYING L''HOSPITAL RULE;

LT X-0   SINX/6X=1/6;;THUS ,,WE CAN GET ANS 1/6;;;;;;;;;;;;;;;

I HOPE YOU WILL UNDERSTAND,,,,,,,,,,,,,,,

AND,ALSO, WILL APPROVE THIS,,,,

AFTER APPLYING TWO TIMES L HOSPITAL RULE;;

YOU WILL GET;;

SINX/6X=1/6

when x->0 dinominator would become 0 so answer becomes infinity