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Verify that the given function satisfies the differential equation y=xlogx-x, y=logx
y = (x logx) - x
y = x (logx -1)
take derivation oin both sides
then dy/dx = (logx-1) + (x (1/x)) since d/dx (uv) = d/dx(u)*v - d/dx (v) * u
so dy/dx = logx -1+1
y'' = logx
if you like my answer approve me. ------ keep smile -----
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