Rinkoo Gupta
Last Activity: 10 Years ago
let f(x) is an even function
then by def f(-x)=f(x)
let g(x)= (f(x))^2
=>Replacing x by -x we get
g(-x)=(f(-x))^2
=> g(-x)=( f(x) )^2 since f(x) is an even fn.
=> g(-x)=g(x)
Now,
let f(x) is an odd function
then by def f(-x)= -f(x)
let g(x)=(f(x))^2
Replacing x by -x we get
g(-x)=(f(-x))^2
=>g(-x)=(-f(x))^2=(f(x))^2
=>g(-x)= (g(x))^2
In this way we see that the squqre of an even or odd function is always an even function.
Thanks & Regards
Rinkoo Gupta
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