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limit x tends to 0 (1/x^2 - 1/(sinx)^2 )
Dear tushar
Ltx→0(1/x^2 - 1/(sinx)^2 )
or
Ltx→0(sin2x-x2)/x2sin2x
or Ltx→0(sin2x-x2)/x4{sin2x/x2}
or Ltx→0(sin2x-x2)/x4 because Ltx→0 sinx/x =1
Use L hosipal rule
limit will be =-1/3
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