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Differential Calculus

f(x)=x^3+e^(x/2). g'(x)=f'1(x) g'(x)=?

Profile image of Prabin Dhakal
13 Years agoGrade
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1 Answer

Profile image of Nirmal Singh.
12 Years ago
We have f’(x) = derivative of x^3 + derivative of e^(x/2) ( sum rule)
= 3x^2 + ½ e^x/2 (Using power rule for I term and chain rule for second term)
So f’(x) = 3x^2 + ½ e^x/2 = g’(x).
As f’(x) = g’(x) given , we get for g’(x) = 3x^2 + ½ e^(x/2) as answer.
Regards,
Nirmal Singh
Askiitians faculty