f(x)=x^3+e^(x/2). g'(x)=f'1(x) g'(x)=?

We have f’(x) = derivative of x^3 + derivative of e^(x/2) ( sum rule)
= 3x^2 + ½ e^x/2 (Using power rule for I term and chain rule for second term)
So f’(x) = 3x^2 + ½ e^x/2 = g’(x).
As f’(x) = g’(x) given , we get for g’(x) = 3x^2 + ½ e^(x/2) as answer.
Regards,
Nirmal Singh
Askiitians faculty