Badiuddin askIITians.ismu Expert
Last Activity: 14 Years ago
Dear chilikuri
cse 1 x<-1
2|x+1|-2x=|2x-1|+1
2-(x+1)-2x=-2x+1+1
2-(x+1)=21
so x=-2
case 2 -1≤x<0
2|x+1|-2x=|2x-1|+1
2(x+1)-2x=-2x+1+1
x=0
but it is not a solution because x=0 is not lie in -1≤x<0
case 3 0≤x
2|x+1|-2x=|2x-1|+1
2(x+1)-2x=2x-1+1
2(x+1)=2(x+1)
which is always true so x≥0 is its solution
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