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solve limit x->0 {(1+sinx)^1/3 - (1 - 2 tanx)^1/4} / (sin x+tan^2x)

solve limit x->0 {(1+sinx)^1/3 - (1 - 2 tanx)^1/4} / (sin x+tan^2x)

Grade:11

2 Answers

jitender lakhanpal
62 Points
7 years ago

hi shree

 

PFA 

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Aniket Thakur
16 Points
7 years ago

use L hospital rule and get the answer which is 1/12

 

 

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