Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Ques. If x^5-x^3+x=2 then x^6 belongs to Soln. x(x^4-x^2+1)=2, multiplying by x^2+1 we get x(x^6+1)=2(x^2+1) =>x^6+1=2(x+1/x)>=4 so x^6 belongs to 3 I cant understand how they factorized it and why multiplied with x^2+1 only Thank u

Ques. If x^5-x^3+x=2 then x^6 belongs to


Soln. x(x^4-x^2+1)=2,


multiplying by x^2+1 we get
x(x^6+1)=2(x^2+1)
=>x^6+1=2(x+1/x)>=4


so x^6 belongs to 3<=x

I cant understand how they factorized it and why multiplied with x^2+1 only


Thank u 

Grade:11

1 Answers

Bijoy das
18 Points
8 years ago

hi Swap Bho,

since we need the interval of x^6 , therefore somehow we need to bring a " x^6" term in the given expression in the easiest possible way. Multiplying with x^2+1 to x^4-x^2+1 brings the expression x^6+1 using the identity a^3+b^3. hence solved in this way.  

 

Thank you

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free