solve:
y''(x^2 +1) = 2xy'
y' = ist derivative
y'' = second derivate!
solve:
y''(x^2 +1) = 2xy'
y' = ist derivative
y'' = second derivate!
Vikas TU , 12 Years ago
Grade 12th Pass
Differential Calculus> differential-eqn...
2 AnswersArun Kumar
substitue y' =u
y''=u'
we get u'=2x/(x*x+1)u
ln(u)=ln(x^2+1)+C
=> u=c(x^2+1)
dy/dx=c(x^2+1)
y=c((x^3)/3+x)+c1
y''=u'
we get u'=2x/(x*x+1)u
ln(u)=ln(x^2+1)+C
=> u=c(x^2+1)
dy/dx=c(x^2+1)
y=c((x^3)/3+x)+c1
Approved Last Activity: 11 Years ago
TEJKIRAT SINGH
substitue y' =uy''=u'we get u'=2x/(x*x+1)uln(u)=ln(x^2+1)+C=> u=c(x^2+1)dy/dx=c(x^2+1)y=c((x^3)/3+x)+c1
Approved Last Activity: 10 Years ago
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