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solve:

y''(x^2 +1) = 2xy'

 

y' = ist derivative

y'' = second derivate!

Vikas TU , 11 Years ago
Grade 12th Pass
anser 2 Answers
Arun Kumar

Last Activity: 10 Years ago

substitue y' =u
y''=u'
we get u'=2x/(x*x+1)u
ln(u)=ln(x^2+1)+C
=> u=c(x^2+1)
dy/dx=c(x^2+1)
y=c((x^3)/3+x)+c1

TEJKIRAT SINGH

Last Activity: 9 Years ago

substitue y' =uy''=u'we get u'=2x/(x*x+1)uln(u)=ln(x^2+1)+C=> u=c(x^2+1)dy/dx=c(x^2+1)y=c((x^3)/3+x)+c1

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