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dy/dx +[(x 2 -1)(y 2 -1)] 1/2 /xy=0

dy/dx +[(x2-1)(y2-1)]1/2/xy=0

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear upendra

dy/dx +[(x2-1)(y2-1)]1/2/xy=0

or  ydy/(y2-1)1/2      =    - dx (x2-1)1/2/x

or ydy/(y2-1)1/2      =    - dx (x2-1)/x(x2-1)1/2

or ydy/(y2-1)1/2      =   x dx /x2(x2-1)1/2     -xdx /(x2-1)1/2    

 

now intigrate

(y2-1)1/2    = tan-1(x2-1)1/2   - (x2-1)1/2    


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