dy/dx +[(x2-1)(y2-1)]1/2/xy=0

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Grade 12Differential Calculus

dy/dx +[(x²-1)(y²-1)]^1/2/xy=0

upendra hembram

16 Years agoGrade 12

1 Answer

Badiuddin askIITians.ismu Expert

16 Years ago

Dear upendra

dy/dx +[(x²-1)(y²-1)]^1/2/xy=0

or ydy/(y²-1)^1/2 = - dx (x²-1)^1/2/x

or ydy/(y²-1)^1/2 = - dx (x²-1)/x(x²-1)^1/2

or ydy/(y²-1)^1/2 = x dx /x²(x²-1)^1/2-xdx /(x²-1)^1/2

now intigrate

(y²-1)^1/2 = tan^-1(x²-1)^1/2 - (x²-1)^1/2

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