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(1-x2)(1-y)dx=xy(1+y)dy
Dear upendra
seperate term
(1-x2)/x dx=y(1+y)/(1-y) dy
(1/x -x) dx={-(y+2) +2/(1-y) }dy
now integrate
lnx -x2/2 =-(y+2)2/2 +-2ln|1-y| +c
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