Differential Calculus
lim x tends to 0 (e- (1+x)^1/x)/tanx
lim x tends to 0 (e- (1+x)^1/x)/tanx
1 Answer
k sesi preetam
(1+x)^1/x = e^(1/x ln(1+x)) solving this limit is no big deal and the answer is e/2.
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