Grade 12Differential Calculus
find the max. $ min. value of
[(x'-x)2 + (1-x')1/2 + (6/x)2]3/2
find the max. $ min. value of
[(x'-x)2 + (1-x')1/2 + (6/x)2]3/2
1 Answer
Pankaj
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Pankaj Singh
askIITians Faculty
Pankaj Singh
askIITians Faculty
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