Dear ramya
limx→∞(Π/2-tan-1x)1/x
or elimx→∞{ln(Π/2-tan-1x)}/x
or elimx→∞{ln(cot-1x)}/x
use L -hospital rule
elimx→∞{-(1+x2)^-1/2}/cot-1X
again use L-Hospital ruleand put limit
=e0
=1
Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
We are all IITians and here to help you in your IIT JEE & AIEEE preparation.
All the best.
Regards,
Askiitians Experts
Badiuddin