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the ans is y/sec3x = x/2 - 1/12( cos6x + sin6x ) + c
equation can be rewritten as dy/dx - 3tan3x y = sin3x + sin3x tan3x
implies integrating factor is exp(D-1(-3tan3x)) = exp(-ln sec3x) = cos3x
which implies y cos3x = D-1(sin3x cos3x + sin23x) = 1/12(-cos3x) + x/2 - 1/12(sin3x)
implies y = 1/2(x sec3x) -1/12(1+ tan3x).
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