Solve: (3xy+y²) dx + (x² + xy) dy = 0

Please give the steps after integration begins.

PS. ignore the previous ques....there was a mistake of square!

dy/dx=-(3xy+y²)/(x²+xy)

put y=vx

dy/dx=v+x(dv/dx)

v+x(dv/dx)=-(3vx²+v²x²)/(x²+vx²)

v+x(dv/dx)=-(3v+v²)/(1+v)

x(dv/dx)=-4v/(1+v)

∫((1+v)/v)dv=-∫(4/x)dx

ln(v)+v=-4lnx+c

(ln(v)+v+lnx⁴)=constant

ln(y/x)+lnx⁴+(y/x)=c.