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lim n~ infinity (1^k+ 2^k+ 3^k+.........+n^k)\ (k*(n^k + 1)

lim n~ infinity (1^k+ 2^k+ 3^k+.........+n^k)\ (k*(n^k + 1)

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1 Answers

Ayush Shaw
33 Points
9 years ago

More generally, we can say:
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ALSO

PUTIN K=1 WE GET

 

LIM = (N^2 + N)/2(N+1)=1/2*1/0=INFINITY

 

PUTING N=K WE GET INFINITY

PINT N=K+1 WE GET iNFINITY

 

tHEREFORTH sINCE THERE ARE GREATER POWERS OF N AT NUMERRATOR W.R.T dINOMINATOR THERE FORTH tHE ANSWER IS INFINITY

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