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Grade:

                        

lim n~ infinity (1^k+ 2^k+ 3^k+.........+n^k)\ (k*(n^k + 1)

8 years ago

Answers : (1)

Ayush Shaw
33 Points
							

More generally, we can say:
powers6.gif [1.5]

ALSO

PUTIN K=1 WE GET

 

LIM = (N^2 + N)/2(N+1)=1/2*1/0=INFINITY

 

PUTING N=K WE GET INFINITY

PINT N=K+1 WE GET iNFINITY

 

tHEREFORTH sINCE THERE ARE GREATER POWERS OF N AT NUMERRATOR W.R.T dINOMINATOR THERE FORTH tHE ANSWER IS INFINITY

8 years ago
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