# Find the Range of x4/ (x8+1) .

Aman Bansal
592 Points
11 years ago

Dear Atul,

The range is all real except the values of x^8+1 = 0 .

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Thanks

Aman Bansal

ATUL KUMAR
29 Points
11 years ago

Dear Aman Bansal

I have already tried finding g(0) then g(1) using g(2) and thus substituting these values but it didn''t helped.

Can you explain how will it work ?

ATUL KUMAR
29 Points
11 years ago

Dear Aman Bansal

I have already tried finding g(0) then g(1) using g(2) and thus substituting these values but it didn''t helped.

Can you explain how will it work ?

I am asking for th RANGE not DOMAIN .

Regards

AK

42 Points
11 years ago

?????????????????

Q.

Find the Range of x4/ (x8+1) .

Sol:-

y=x4/x8+1

y=x4-8+1

y=x-4+1

y=1/x4+1

y=(1+x4)/x4

x4y=1+x4

x4+x4y+1=0

use b2-4ac formula

a=x4,b=x4,c=1

(x4)2-4x4.10<0(<means lessthan or equal to because in my laptop doesn''t support to type less than or equal to )

x8-4x4<0

x8<4x4

x<4x^4/8

x<4x^1/2

x/x^-1/2<0

x^1/2<0

range is (-,0]

ATUL KUMAR
29 Points
11 years ago

I don''t understand What should I say for the NONSENSE you have done above. Are you aware of what have you done and to what result you have reached ??

y=x4/x8+1

y=x4-8+1

Whats this ??

x^1/2<0

range is (-∞,0]

HORRIBLE MURDER OF MATHEMATICS !

Can √x can ever be less than 0 ??

One more thing range is the Group of possible values of f(x) not x !!

42 Points
11 years ago

?????the range is all real numbers

Vidyasagar Mohanraj
35 Points
11 years ago

For functions like these its best to graph them using calculator to find the range it shows the range is all real numbers