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A drop with initial mass M falls under the action of the force of gravity and evaporates uniformly losing a mass m each second.What is the work performed by the force of gravity during the time interval from the start to the complete evaporation of the drop?(air resistances may be neglected).The answer is g2(M3/6m2)....plz solve

Anirban Mukherjee , 12 Years ago
Grade 12
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