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Let S = {1, 2, 3, 4}. The total number of unordered pairs of disjoint subsets of S is equal to (A) 25 (B) 34 (C) 42 (D) 41
ans :- (D) 41 because Each element in either (A) or (B) or neither So total ways = 34 = 81 A = B if A = B = Φ (1 case) otherwise A and B are interchangeable. so n = 1 +(81-1)/2 = 41
ans :- (D) 41
because Each element in either (A) or (B) or neither
So total ways = 34 = 81
A = B if A = B = Φ (1 case)
otherwise A and B are interchangeable.
so n = 1 +(81-1)/2 = 41
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