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y= √( (1-sinx)/(1+sinx)) , prove that (d y/dx)+ Sec 2 ((π/4)-x)=0
Question is wrong ! y=√((1-sinx)/(1+sinx)) 1-sinx/1-sinx= = 1-cos(90-x)/1+cos(90-x) = 1-1+2Sin2(45-(x/2))/1+2cos2(45-(x/2))-1 = [tan(45-x/2)]2 hence y= [tan2(45-x/2)]1/2 y= tan (45-x/2) dy/dx= sec2(45-x/2) . {0-1/2} dy/dx= -0.5sec2(45-x/2) 0r dy/dx+0.5sec2(45-x/2) = 0
Question is wrong !
y=√((1-sinx)/(1+sinx))
1-sinx/1-sinx=
= 1-cos(90-x)/1+cos(90-x)
= 1-1+2Sin2(45-(x/2))/1+2cos2(45-(x/2))-1
= [tan(45-x/2)]2
hence y= [tan2(45-x/2)]1/2
y= tan (45-x/2)
dy/dx= sec2(45-x/2) . {0-1/2}
dy/dx= -0.5sec2(45-x/2)
0r dy/dx+0.5sec2(45-x/2) = 0
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