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Grade: 12th Pass
        

[x/2]+[x/3]+[x/5]=31x/30, where [x] is the greatest integer less than or equal to x, the number of possible values of x is,

7 years ago

Answers : (1)

Arun Kumar
IIT Delhi
askIITians Faculty
256 Points
							see right part has to be integer s x is multiple of 30 
no since 30 is factor of 2,3,5
so left part becomes
31[x]/30
=> n30 where n belongs to integer
5 years ago
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