A balloon is rising vertically above a level, a straight road a constant rate 1 m/s. Just when the balloon is 65m above the ground, a bicycle moving at a constant rate of 17 m/s passes under it. How fast is the distance b/w the bicycle and balloon increasing 3 seconds later?

A)11 m/s

B) 9 m/s

C) 13 m/s

D) 15 m/s

Question

A balloon is rising vertically above a level, a straight road a constant rate 1 m/s. Just when the balloon is 65m above the ground, a bicycle moving at a constant rate of 17 m/s passes under it. How fast is the distance b/w the bicycle and balloon increasing 3 seconds later?

A)11 m/s

B) 9 m/s

C) 13 m/s

D) 15 m/s

Arun Kumar · Answer

we do this by coordinate geometry baloon (0,65+1*t) bicycle (17t,0) z^2=289*t^2+(65+t)^2 2zdz/dt=289*2*t+2(65+t) we can dz/dt=11

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