0

Guest

Courses New

A balloon is rising vertically above a level, a straight road a constant rate 1 m/s. Just when the balloon is 65m above the ground, a bicycle moving at a constant rate of 17 m/s passes under it. How fast is the distance b/w the bicycle and balloon increasing 3 seconds later? A)11 m/s B) 9 m/s C) 13 m/s D) 15 m/s

A balloon is rising vertically above a level, a straight road a constant rate 1 m/s. Just when the balloon is 65m above the ground, a bicycle moving at a constant rate of 17 m/s passes under it. How fast is the distance b/w the bicycle and balloon increasing 3 seconds later?


A)11 m/s


B) 9 m/s


C) 13 m/s


D) 15 m/s

Grade:

1 Answers

Arun Kumar IIT Delhi
askIITians Faculty 256 Points
8 years ago
we do this by coordinate geometry baloon (0,65+1*t)
bicycle (17t,0)
z^2=289*t^2+(65+t)^2
2zdz/dt=289*2*t+2(65+t)
we can dz/dt=11

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Differential Calculus

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More