f(x+y2) = f(x) + [f(y)]2 f is not 0 f is diff. at 0 then find f ' (0)

BACK

Grade 12Differential Calculus

f(x+y²) = f(x) + [f(y)]²

f is not 0 f is diff. at 0 then find f ' (0)

Dinesh Gupta

16 Years agoGrade 12

1 Answer

Badiuddin askIITians.ismu Expert

16 Years ago

Dear dinesh

f(x+y²) = f(x) + [f(y)]²

put y=x

f(x+x²) = f(x) + [f(x)]²

differentiate

(1+2x)f'(x+x²) = f'(x) + 2f'(x)[f(x)]

put x=0

f'(0)=f'(0) + 2'f(0)[f(0)]

or f'(0)[f(0)]=0

so f'(0) =0

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
We are all IITians and here to help you in your IIT JEE preparation.

All the best.

Regards,
Askiitians Experts
Badiuddin