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limit x tends to 0 [sinx/x]
the value is little bit less than one. on differentiating sinx-x we get cosx-1 whose value is less than one
1 its a direct formula
ans is 0 see from the graph that y=x is always upper than sinx as lim tends to 0 six/x is smaller than 1 (sinx is smaller than x) hence [0.something] = 0
ans is 0
see from the graph that y=x is always upper than sinx
as lim tends to 0 six/x is smaller than 1 (sinx is smaller than x)
hence [0.something] = 0
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