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In a triangle ABC, AB=AC and the length of the median from B to the side AC is 1. Find the cosine of the angle A for which the area of triangle is minimun.
Dear harshit cosA =((b/2)2 +c2 -1) /bc b=c so cos A = 5/4 -1/b2 b2=4/(5-4cosA) nor area of triangle is =1/2 bc sinA =1/2 b2 sinA =2sinA/(5-4cosA) now differntiate and value of cos A for minimum value of area Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best. Regards, Askiitians Experts Badiuddin
Dear harshit
cosA =((b/2)2 +c2 -1) /bc
b=c
so cos A = 5/4 -1/b2
b2=4/(5-4cosA)
nor area of triangle is =1/2 bc sinA
=1/2 b2 sinA
=2sinA/(5-4cosA)
now differntiate and value of cos A for minimum value of area
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best. Regards, Askiitians Experts Badiuddin
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