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Grade: 12
        range of function :- x^2+4x

7/x^2+x+1
6 years ago

Answers : (1)

Sher Mohammad
IIT Delhi
askIITians Faculty
174 Points
							f(x)=x^2+4x+ 7/x^2+x+1
f'(x)=(2x+4)(x^2+x+1)-(2x+1)(x^2+4x+ 7)/(x^2+x+1)^2
f'(x)=0 , gives x=-2
f(-2)=4-8+7/(4-2+1)= 3/3 =1
f(0)=7
range=[1,7]

4 years ago
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