If lim x tends 0(acosx + bxsinx - 5)/x^5 is a finite value, find a & b
Saideep Ch , 13 Years ago
Grade 11
3 Answers
nikhil arora
Last Activity: 13 Years ago
a=5 , b belongs to R
G Narayana Raju
Last Activity: 13 Years ago
by L Hôpitals rule,
after differentiating five times ,as the limit tends to zero the value tends to zero.so the value of a and b can be anything.
Neha Gaur
Last Activity: 12 Years ago
as xtends to 0,acosx +bxsinx -5)-->a-5 & denominator-->0
limit is finite if a-5=0i.e. a=5 so that it gets 0/0 form &limit can be found
lim x-->0 (acosx + bxsinx -5)/x^5
(-asinx+b(xcosx+sinx))/5x^4
(-acosx+b(x(-sinx)+2cosx))/20x^3
=limx-->0 (-acosx-bxsinx+2bcosx)/20x^3
similarly (-a+2b)=0=>b=5/2
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