Neha Gaur
Last Activity: 12 Years ago
as xtends to 0,acosx +bxsinx -5)-->a-5 & denominator-->0
limit is finite if a-5=0i.e. a=5 so that it gets 0/0 form &limit can be found
lim x-->0 (acosx + bxsinx -5)/x^5
(-asinx+b(xcosx+sinx))/5x^4
(-acosx+b(x(-sinx)+2cosx))/20x^3
=limx-->0 (-acosx-bxsinx+2bcosx)/20x^3
similarly (-a+2b)=0=>b=5/2