MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping
Menu
Grade: 
        
T=290+80e-kt 


then no. of solution of modulus T= Modulus f(t) and T2+t2=1600 is
10 years ago

Answers : (1)

View Solution
Askiitian.Expert Rajat
24 Points 
							
Hi Sanjeev,


 


Please clarify what is f(t) in this case


Regards
10 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Other Related Questions on Differential Calculus

Y= (1+x/1-x) 1/2 Prove that (1-x 2 )y n - [2(n-1)x +1 ]y n-1 - (n-1)(n-2)y n-2 =0 Answer & Earn Cool Goodies
Derivative of tan–1(x/(1+x 2 ) ½ )with respect to sin–1 (3x – 4x3) Answer & Earn Cool Goodies
Find the local maximum of f(x)={ log(x) } / x . I tried but could only find local minima .After...
Find the point on the plane 4x+3y+z=2 that is closest to (1,-1,1).
2x-5 /(x-1)(x-2)(x-5) find out the partial fraction of above function
View all Questions »


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 51 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers To Win!!! Click Here for details