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find dy/dx for y=a x az.....∞ It is 'a' raised to 'x' then 'a' raised to 'x' upto infinity
y=a^x^a^x .... upto inf.. => y=a^xy takinh log on both sides lny=xylna now differentiating wrt x , we get 1/y.dy/dx=xlna.dy/dx+ylna => dy/dx= y^2lna/(1-xylna)
y=a^x^a^x .... upto inf..
=> y=a^xy
takinh log on both sides
lny=xylna
now differentiating wrt x , we get
1/y.dy/dx=xlna.dy/dx+ylna
=> dy/dx= y^2lna/(1-xylna)
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