Differential Calculus> find period...

let f(x +p) =1 + { 2-3f(x) - 3(f(x))^2 - (f(x))^3}^1/3, for all x belongs to R,where p >0 then find period of f(x).

manuj mittal , 13 Years ago

Grade

1 Answers

Jitender Singh

Last Activity: 10 Years ago

Ans: 2p

$f(x+p) = 1 + (2-3f(x)+3f(x)^{2}-f(x)^{3})^{\frac{1}{3}}$

$f(x+p) = 1 + (1+(1-f(x))^{3})^{\frac{1}{3}}$

$x\rightarrow x+p$

$f(x+p+p) = 1 + (1+(1-f(x+p))^{3})^{\frac{1}{3}}$

$1-f(x+p) = -(1+(1-f(x))^{3})^{\frac{1}{3}}$

$f(x+2p) = 1 + (1+(-(1+(1-f(x))^{3}))^{\frac{1}{3}}$

$f(x+2p) = 1-1+f(x)=f(x)$

So, the time period of f(x) is 2p.

Thanks & Regards

Jitender Singh

IIT Delhi

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Differential Calculus> find period...

let f(x +p) =1 + { 2-3f(x) - 3(f(x))^2 - (f(x))^3}^1/3, for all x belongs to R,where p >0 then find period of f(x).

manuj mittal , 13 Years ago

Jitender Singh

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