Ashwin Muralidharan IIT Madras
Last Activity: 13 Years ago
Hi Manuj,
4 & 8 are both incorrect. It must be 16.
Lets see how.....
In the equation given, replace x by "x-3/2".
So we have f(2x) + f(2x+4) = 2.
Now replace x by "x+2"
So we have f(2x+4) + f(2x+8) = 2.
Subtract these two equations, and we get f(2x+8) = f(2x).
So the period of f(2x) is 8.
Hence the period of f(x) = f[1/2(2x)] is 8/(1/2) = 16.
So 16 is the period of f(x).
Hope it helps.
Wish you all the best.
Regards,
Ashwin (IIT Madras).