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The function f(x)= k Isin xI + k2Icos xI +g(q) has period = pi/2, then k is:
(a) 2 (b) 1 (c)3 (d) none of these. How?
Hi Aditi,
g(q) is a constant function, and hence always periodic.
So the period of k|sinx| + k2|cosx| should be pi/2.
Which is possible only when k=1
Since the period of f(x) = |sinx| + |cosx| is pi/2
Note that f(x+pi/2) = f(x) for k=1 only.
Hence Option (B).
Hope that helps.
Best Regards,
Ashwin (IIT Madras).
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