let dere be a qoutient of 2 natural no. in which denominator is one less than d square of numerator. if we add 2 to both numerator and denominator,qoutient will excess2/3. if we subtract 3 from both numerator and denominator qoutient will lie b/w 0 and 1/10.determine d qoutient.

Hi Manju,

Let the Quotiesnt be M/N

N = M²-1.

(M+2)/(N+2) > 2/3 & 0 < (M-3)/(N-3) < 1/10

So 3M+6>2N+4

or 3M+2 > 2N

or 3M+2 > 2M²-2

So 2M²-3M-4<0 or (3-√41)/4<M<(3+√41)/4

So M can be 1 or 2, correspondingly for which N will be 0 or 3.

Both are not possible.

Hence there is no quotient which satisfies the given conditions.

Best Regards,

Ashwin (IIT Madras).

first of all...plzz do d correction in my name..........its manuj......and i hv an answer for dis problem which is 4/15.actually i hv doubt in a line dere........dere is given tht "if we add 2 to both numerator and denominator ,qoutient will excess 2/3".....what does it mean......???.....i mean i m not getting dis line clearly ..."qoutient will excess2/3".....do something so tht we can get answer 4/15.

Hi Manuj,

Pardon my typing error of your name.

The quotient is M/N. When you add 2 to both Nr and Dr it will excess 2/3 means (M+2)/(N+2) > 2/3.

Now watever you do, this problem with the given conditions cannot have an answer. Either the conditions are wrong or the answer is wrong.

The source from where you got this can have a typing error too.

Have confidence in your working dude, and you can have some trust in my working as well :-)

Hope it helps.

Best Regards,

Ashwin (IIT Madras).

Hi Manuj,

Yes,I agree with Ashwin,this problem with the given conditions cannot have an answer. Either the conditions are wrong or the answer is wrong.