f(x)=log(x+(x2+1)1/2) is (a) even function (b) odd fubction (c)periodic function (d)neither even nor odd functionExplain ur answer pls.

Hi Aditi,

Note that √(x²+1) - x = 1/[√(x²+1) + x]

Hence log(√(x²+1) - x) = -log[√(x²+1) + x]

Hence f(-x) = -f(x).

Hence f(x) is odd.

Hope that helps.

Best Regards,

Ashwin (IIT Madras).

Approved