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f(x)=log(x+(x2+1)1/2) is (a) even function (b) odd fubction (c)periodic function (d)neither even nor odd function
Explain ur answer pls.
Hi Aditi,
Note that √(x2+1) - x = 1/[√(x2+1) + x]
Hence log(√(x2+1) - x) = -log[√(x2+1) + x]
Hence f(-x) = -f(x).
Hence f(x) is odd.
Hope that helps.
Best Regards,
Ashwin (IIT Madras).
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