Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
In Differential Calculus by Arihant Publication Pg.no. 88 - Q.no. 2,3,5Pg.no. 90 - Q.no. 15,17Pg.no. 91 - Q.no. 29FOR THOSE WHO DONT HAVE THIS BOOK:NOTE: D is same as (d/dx)f(-1)(x) is same as f inverse of x^3 means 'power 3''pi' is same as 22/7 or 3.14'sqrt.' is same as square root of
1) Let f(x) = (2x-pi)^3 + 2x - cosx. The value of D(f(-1)(x)) at x = pi is: a) 3 pi^2 + 2 b) -2 c) 1/(3pi^2 + 2) d) 1/32) A function f:R->R satisfies sinx cosy (f(2x+2y) - f(2x-2y)) = cosx siny (f(2x+2y) + f(2x- 2y)). If f'(0)=1/2, then: a) f''(x) - f'(x) =0 b) 4f''(x) + f(x) =0 c) f''(x) + f(x) =0 d) 4f''(x) - f(x) =03. If y= sec(-1)((x-1)/(x+1)) + sin(-1)((x-1)/(x+1)), then Dx=? a) 1 b) 0 c) (x-1)/(x+1) d) (x+1)/(x-1)4. If sqrt.(x^2 + y^2) = a e^(tan(-1)(y/x)), a>0 then y''(0) is: a)(a/2) e^(-pi/2) b) a e^(pi/2) c)(-2 e^(-pi/2))/a d) does not exist5. If P(x) is a polynomial such that P(x^2+1)={P(x)}^2 + 1 and P(0)=0 then P'(0) is equal to: a) 1 b)0 c) -1 d)none of these6)Let f:R->R be a differential function satisfying f(y).f(x-y)=f(x) for all x,y and f'(5)=q and p.f(0)=f'(0) then f(5) is: a) p^2/q b) p/q c) q/p d) q.Please help me askIITians.
Dear Abhishek,
1) It's "pi". (2) pi is _not_ 22/7
Now that that's over with, first find
df(x)/dx = 3(2x - pi)^2 * 2 + 2 + sin(x)
Let x = pi to get 3*pi^2 * 2 + 2 + 0 = 6pi^2 + 2
Best Of Luck...!!!!
Cracking IIT just got more exciting,It’s not just all about getting assistance from IITians, alongside Target Achievement and Rewards play an important role. ASKIITIANS has it all for you, wherein you get assistance only from IITians for your preparation and winexciting gifts by answering queries in the discussion forums. Reward points 5 + 15 for all those who upload their pic and download the ASKIITIANS Toolbar, just a simple click here to download the toolbar….
So start the brain storming…. become a leader with Elite Expert League ASKIITIANS
Thanks
Aman Bansal
Askiitian Expert
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !