Pratham Ashish
Last Activity: 15 Years ago
hi,
If a real-valued function ƒ is continuous on a closed interval [a, b], differentiable on the open interval (a, b), and ƒ(a) = ƒ(b), then there exists a c in the open interval (a, b) such that
so differentiating given f(x) with respect to x, we get
(x+3)e^-(1/2)x + x*e^-(1/2)x - (0.5) x(x+3)e^-(1/2)x = 0
taking e^-(1/2)x common ,then we will left with
(x+3) + x - (0.5) x(x+3) = 0
after solving this eqn in x ,u will get
x=3, x = -2
since for validation of rolles theorem this value of x shud lie in the given interval
c = -2..................