 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
The function f(x)=x(x+3)e^-(1/2)x satisfies all the condition of of rolles theoram in [-3,0].The value of c is

```
11 years ago

```							hi,
If a real-valued function ƒ is continuous on a closed interval [a, b], differentiable on the open interval (a, b), and ƒ(a) = ƒ(b), then there exists a c in the open interval (a, b) such that $f'(c) = 0.\,$

so differentiating given f(x) with respect to x, we get
(x+3)e^-(1/2)x + x*e^-(1/2)x - (0.5) x(x+3)e^-(1/2)x = 0

taking e^-(1/2)x common ,then we will left with

(x+3) + x - (0.5) x(x+3) = 0

after solving this eqn in x ,u will get
x=3, x = -2

since for validation of rolles theorem this value of x shud lie in the given interval
c = -2..................

```
11 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Differential Calculus

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 51 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions