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The function f(x)=x(x+3)e^-(1/2)x satisfies all the condition of of rolles theoram in [-3,0].The value of c is
hi, If a real-valued function ƒ is continuous on a closed interval [a, b], differentiable on the open interval (a, b), and ƒ(a) = ƒ(b), then there exists a c in the open interval (a, b) such that so differentiating given f(x) with respect to x, we get (x+3)e^-(1/2)x + x*e^-(1/2)x - (0.5) x(x+3)e^-(1/2)x = 0 taking e^-(1/2)x common ,then we will left with (x+3) + x - (0.5) x(x+3) = 0 after solving this eqn in x ,u will get x=3, x = -2 since for validation of rolles theorem this value of x shud lie in the given interval c = -2..................
hi,
If a real-valued function ƒ is continuous on a closed interval [a, b], differentiable on the open interval (a, b), and ƒ(a) = ƒ(b), then there exists a c in the open interval (a, b) such that
so differentiating given f(x) with respect to x, we get
after solving this eqn in x ,u will get
x=3, x = -2
since for validation of rolles theorem this value of x shud lie in the given interval
c = -2..................
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