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If the edge of a cube increased at the rate of 60cm per second at what rate the volume is increasing when the edge is 90cm If the edge of a cube increased at the rate of 60cm per second at what rate the volume is increasing when the edge is 90cm
If the edge of a cube increased at the rate of 60cm per second at what rate the volume is increasing when the edge is 90cm
hi, ur queswtion is a simple use of derivatives rate of increase of side say 'a', is da/dt = 60 since volume of a cube , v = a^3 so dv/dt = 3*a2 * da/dt here dv/dt = rate of increase of volume so dv/dt = 3* 90*90* 60 = 1458000 cubic centimeter / sec
hi,
ur queswtion is a simple use of derivatives
rate of increase of side say 'a', is da/dt = 60
since volume of a cube , v = a^3
so dv/dt = 3*a2 * da/dt
here dv/dt = rate of increase of volume
so dv/dt = 3* 90*90* 60
= 1458000 cubic centimeter / sec
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