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Show that the min value of 4x2+4x |sin@| - cos2@ is -1

Tushar Watts , 15 Years ago
Grade 12
anser 1 Answers
Pratham Ashish

Last Activity: 15 Years ago

hi,

p = 4x2+4x |sin@| -  cos2@  is -1

   = 4x2+4x |sin@| -1 + sin2@                 (  sin2@  = |sin@| ^2 )

   =4x2+4x |sin@| + |sin@| ^2 - 1

   = ( 2x + |sin@| )^2  -1

 give min . value when the squre part will be equal to zero.

 hence min. value = -1 

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