Show that the min value of 4x2+4x |sin@| - cos2@ is -1
Show that the min value of 4x2+4x |sin@| - cos2@ is -1
Tushar Watts , 15 Years ago
Grade 12
Differential Calculus> App of deriviatives...
1 AnswersPratham Ashish
Last Activity: 15 Years ago
hi,
p = 4x2+4x |sin@| - cos2@ is -1
= 4x2+4x |sin@| -1 + sin2@ ( sin2@ = |sin@| ^2 )
=4x2+4x |sin@| + |sin@| ^2 - 1
= ( 2x + |sin@| )^2 -1
give min . value when the squre part will be equal to zero.
hence min. value = -1
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